Ta có: \(\dfrac{2+\dfrac{x}{5}}{5}=\dfrac{x-\dfrac{1}{5}}{12}\)
\(\Rightarrow\left(2+\dfrac{x}{5}\right)12=\left(x-\dfrac{1}{5}\right)5\)
\(\Rightarrow24+\dfrac{12x}{5}=5x-1\)
\(\Rightarrow\dfrac{12x}{5}-5x=-24-1\)
\(\Rightarrow x\left(\dfrac{12}{5}-5\right)=-25\)
\(\Rightarrow x.\dfrac{-13}{5}=-25\)
\(\Rightarrow x=\dfrac{125}{13}\)
Vậy \(x=\dfrac{125}{13}.\)
\(\dfrac{2+\dfrac{x}{5}}{5}=\dfrac{x-\dfrac{1}{5}}{12}=\left(2+\dfrac{x}{5}\right).\dfrac{1}{5}=\left(x-\dfrac{1}{5}\right).\dfrac{1}{12}\)
\(\Rightarrow\dfrac{2}{5}+\dfrac{x}{25}=\dfrac{x}{12}-\dfrac{1}{60}\)
\(\Rightarrow\dfrac{x}{25}-\dfrac{x}{12}=-\dfrac{2}{5}-\dfrac{1}{60}\)
\(\dfrac{x}{25}-\dfrac{x}{12}=-\dfrac{5}{12}\)
\(\Rightarrow\dfrac{12x}{300}-\dfrac{25x}{300}=-\dfrac{125}{300}\)
\(\Rightarrow12x-25x=-125\\\)
\(-13x=-125\Rightarrow x=\dfrac{-125}{-13}=\dfrac{125}{13}\)
