Ta có:
\(-\left(-\dfrac{1}{6}\right)^{100}=-\left(\dfrac{1}{6}\right)^{100}=-\left[\left(\dfrac{1}{6}\right)^2\right]^{50}=-\left(\dfrac{1}{36}\right)^{50}\)
\(-\left(-\dfrac{1}{8}\right)^{150}=-\left(\dfrac{1}{8}\right)^{150}=-\left[\left(\dfrac{1}{8}\right)^3\right]^{50}=-\left(\dfrac{1}{512}\right)^{50}\)
Mà: \(\dfrac{1}{36}>\dfrac{1}{512}\)
\(\Rightarrow\left(\dfrac{1}{36}\right)^{50}>\left(\dfrac{1}{512}\right)^{50}\)
\(\Rightarrow-\left(\dfrac{1}{36}\right)^{50}< -\left(\dfrac{1}{512}\right)^{50}\)
\(\Rightarrow-\left(\dfrac{-1}{6}\right)^{100}< -\left(\dfrac{-1}{8}\right)^{150}\)