\(CaCO_3\rightarrow CaO+CO_2\)
\(m_{CaO}=10^6.85\%=850000\left(g\right)\Rightarrow n_{CaO}=15178,6\left(mol\right)\)
\(m_{CaCO3}=n_{CaO}=15178,6\left(mol\right)\)
\(n_{CaCO3\left(tt\right)}=\frac{15178,6.100}{85}=17857,14\left(mol\right)\)
\(m_{CaCO3}=1785714,3\left(g\right)\)
\(\Rightarrow m_{da.voi}=\frac{1785714.100}{94}=1899696,05\left(g\right)=1,899\left(tan\right)\)