TT: 50ml = 0,05L
a) Tính số mol chất tan:
ADCT: CM = \(\dfrac{n}{V}\) → n = \(C_M\) x V → \(n_{CuSO4}\) = 1 x 0,05 = 0,05 mol
\(m_{CuSO4}\) = n x M = 0,05 x (64+32+16x4) = 8g
b) tìm khối lượng chất tan:
ADCT: C% = \(\dfrac{m_{ct}}{m_{dd}}\) x 100% → \(m_{ct}\) = \(\dfrac{C\%\times m_{dd}}{100\%}\) = \(\dfrac{10\times50}{100\%}\) = 5g
\(m_{dm}\) = \(m_{dd}\) - \(m_{ct}\) = 50-5 = 45g