(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac.
(1/a + 1/b + 1/c)2 = 1/a2 + 1/b2 + 1/c2 + 2(1/ab + 1/bc + 1/ac) = 4
<=> 1/a2 + 1/b2 + 1/c2 + 2(bcac + abac + abbc)/(a2b2c2) = 4
<=> 1/a2 + 1/b2 + 1/c2 + 2abc(a + b + c)/(a2b2c2) = 4
<=> 1/a2 + 1/b2 + 1/c2 + 2 = 4
(vì abc(a + b + c) = a2 b2 c2)
<=> 1/a2 + 1/b2 + 1/c2 = 2