\(a,VT=9+4\sqrt{5}=\sqrt{5^2}+2.2\sqrt{5}+2^2=\left(\sqrt{5}+2\right)^2=VP\left(dpcm\right)\)
\(b,\sqrt{9-4\sqrt{5}}-\sqrt{5}=-2\)
\(\Leftrightarrow\sqrt{9-4\sqrt{5}}=\sqrt{5}-2\)
Ta có : \(VT=\sqrt{9-4\sqrt{5}}=\sqrt{\sqrt{5^2}-2.2\sqrt{5}+2^2}=\sqrt{\left(\sqrt{5}-2\right)^2}=\left|\sqrt{5}-2\right|=\sqrt{5}-2=VP\left(dpcm\right)\)