\(x^3+2\ge3x\)
\(\Rightarrow x^3+2-3x=0\)
\(\Rightarrow x^3-3x^2+3x-1+3x^2-6x+3=0\)
\(\Rightarrow\left(x^3-3x^2+3x-1\right)+3\left(x^2-2x+1\right)=0\)
\(\Rightarrow\left(x-1\right)^3+3\left(x-1\right)^2\ge0\)
\(\Rightarrow\left(x-1\right)^2\left[\left(x-1\right)+3\right]\ge0\)
\(\Rightarrow\left(x-1\right)^2\left(x+2\right)\ge0\forall\)x dương