Từ \(\dfrac{a+b}{c+d}=\dfrac{b+c}{d+a}\Rightarrow\left(a+b\right)\left(d+a\right)=\left(b+c\right)\left(c+d\right)\)
\(\Rightarrow ad+a^2+bd+ba=bc+bd+c^2+cd\)
\(\Rightarrow a^2+a\left(b+d\right)=c^2+c\left(b+d\right)\)
Vì đt trên bằng nhau : \(\Rightarrow a\left(b+d\right)=c\left(b+d\right)\Leftrightarrow a=c\)