\(\left(a.a\right)-\left[\left(a-1\right)\left(a+1\right)\right]=1\)
\(\Leftrightarrow a^2-a^2+1=1\)
\(\Leftrightarrow1=1\) ( luôn đúng )
\(\Rightarrow a\in R\)
Vậy...
a.a - [(a-1)(a+1)]
= [(a-1+1)a]-[(a-1)(a+1)]
= [(a-1)a + 1.a] - [(a-1)a + (a-1).1]
= (a-1)a + a - (a-1)a - (a - 1)
= a - a + 1
= 1