Ta có:
\(3^{2005}+3^{2006}+3^{2007}+3^{2008}+3^{2009}\)
\(=3^0.3^{2005}+3^1.3^{2005}+3^2.3^{2005}+3^3.3^{2005}\) \(+3^4.3^{2005}\)
\(=3^{2005}\left(3^0+3^1+3^2+3^3+3^4\right)\)
\(=3^{2005}.121=3^{2005}.11.12⋮11\)
Vậy \(3^{2005}+3^{2006}+3^{2007}+3^{2008}+3^{2009}⋮11\) (Đpcm)