Ta co : \(\dfrac{2\sqrt{x.\left(x-z\right)}}{2}\le\dfrac{x+x-z}{2}\)
\(\dfrac{2\sqrt{z\left(y-x\right)}}{2}\le\dfrac{z+y-x}{2}\)
VT≤\(\dfrac{2x-z}{2}+\dfrac{z+y-x}{2}=\dfrac{2x-z+z+y-x}{2}\)
=\(\dfrac{x+y}{2}\le\sqrt{xy}\)
=> DPCM
Toan bo dung bdt Co Si nha