\(A=\dfrac{1}{x^3+y^3+xy}\le\dfrac{1}{xy\left(x+y\right)+xy}=\dfrac{1}{xy\left(x+y+1\right)}=\dfrac{1}{2xy}\le\dfrac{1}{\dfrac{\left(x+y\right)^2}{2}}=\dfrac{1}{\dfrac{1}{2}}=2\)
Vậy GTLN của A là 2 . Dấu = xảy ra khi \(x=y=\dfrac{1}{2}\)
\(A=\dfrac{1}{x^3+y^3+xy}\le\dfrac{1}{xy\left(x+y\right)+xy}=\dfrac{1}{xy\left(x+y+1\right)}=\dfrac{1}{2xy}\le\dfrac{1}{\dfrac{\left(x+y\right)^2}{2}}=\dfrac{1}{\dfrac{1}{2}}=2\)
Vậy GTLN của A là 2 . Dấu = xảy ra khi \(x=y=\dfrac{1}{2}\)
Tim gia tri nho nhat cua bieu thuc :
f(x,y)=\(\dfrac{3x^2+2y^2}{2005xy}\) voi xy \(\ne\) 0
goi \(x_1,x_2\) la cac nghiem cua phuong trinh :
12\(x^2-6mx+m^2-4+\dfrac{12}{m^2}=0\left(m>0\right)\)
Tim m de A=\(x_1^3+x_2^3\) dat gia tri lon nhat , gia tri nho nhat
tim gia tri nho nhat cua bieu thuc P=\(\left(1+x\right)\left(1+\dfrac{1}{y}\right)+\left(1+y\right)\left(1+\dfrac{1}{x}\right)\) trong do x,y la cac so duong thoa man \(x^2+y^2=1\)
Cho bieu thuc \(P=\left(\dfrac{3}{x-1}-\dfrac{1}{\sqrt{x}+1}\right):\dfrac{1}{\sqrt{x}+1}\)
a.Neu dkxd va rut gon bieu thuc P
b.Tim cac gia tri cua x de \(P=\dfrac{5}{4}\)
c.Tim gia tri nho nhat cua bieu thuc :\(M=\dfrac{x+12}{\sqrt{x}-1}\cdot\dfrac{1}{P}\)
Cho P = \(\left(\dfrac{1}{\sqrt{x}+1}-\dfrac{2\sqrt{x}-2}{x\sqrt{x}-\sqrt{x}+x-1}\right)\): \(\left(\dfrac{1}{\sqrt{x}-1}+\dfrac{2}{x-1}\right)\)
a/ Tim DKXD va rut gon P
b/ Tim cac gia tri nguyen cua x de P co gia tri nguyen
tim x de bieu thuc \(\dfrac{1}{x-\sqrt{x}+1}\) dat gia tri lon nhat.
MAI THI ROI! HELP ME
tim mim A=\(\dfrac{xy}{z}+\dfrac{yz}{x}\)+\(\dfrac{xz}{y}\)voi x,y,z >0 va x^2+y^2+z^2=1
Rut gon P=\(\dfrac{3x+6\sqrt{x}}{x+\sqrt{x}-2}-\dfrac{\sqrt{x-1}}{\sqrt{x}+2}+\dfrac{\sqrt{x}+2}{1-\sqrt{x}}\)
Tim x de P dat gia tri lon nhat
Cho cac so thuc duong x,y,z thoa man :\(\sqrt{x^2+y^2}+\sqrt{y^2+z^2}+\sqrt{z^2+x^2=2015}\)
Tim ja tri nho nhat cua bieu thuc :\(T=\dfrac{x^2}{y+x}+\dfrac{y^2}{z+x}+\dfrac{z^2}{x+y}\)