nCa(OH)2 = 0.31 mol
TH1: Chỉ tạo ra CaSO3
Đặt : nSO2 = x mol
Ca(OH)2 + SO2 --> CaSO3 + H2O
___________x_______x
m dd tăng = mCaSO3 - mSO2 = 15.52
<=> 120x - 64x = 15.52
<=> x = 0.28
VSO2 = 6.272 (l)
TH2 : Tạo ra hai muối
Ca(OH)2 + SO2 --> CaSO3 + H2O
0.28_______0.28____0.28
=> nCa(OH)2 (cl) = 0.03 mol
Ca(OH)2 + 2SO2 --> Ca(HSO3)2
0.03________0.06
VSO2 = ( 0.28+0.06) *22.4 = 7.616 (l)