Ta có: AB // CD
\(\Rightarrow\left\{{}\begin{matrix}\widehat{A}+\widehat{D}=180^o\left(trongcungphia\right)\\\widehat{C}+\widehat{B}=180^o\left(trongcungphia\right)\end{matrix}\right.\)(AD là cát tuyến; BC là cát tuyến)
Mà \(\widehat{A}=100^o;\widehat{C}=60^o\)
\(\Rightarrow\left\{{}\begin{matrix}\widehat{D}=80^o\\\widehat{B}=120^o\end{matrix}\right.\)
Vậy...