\(cosB=\dfrac{BA^2+BC^2-AC^2}{2\cdot BA\cdot BC}\)
=>\(28^2+35^2-AC^2=2\cdot28\cdot35\cdot\dfrac{1}{2}=28\cdot35\)
=>\(AC=7\sqrt{21}\left(cm\right)\)
\(cosC=\dfrac{CA^2+CB^2-AB^2}{2\cdot CA\cdot CB}=\dfrac{1029+35^2-28^2}{2\cdot7\sqrt{21}\cdot35}=\dfrac{\sqrt{21}}{7}\)
=>sin C=2 căn 7/7
=>tan C=2 căn 3/3
=>cot C=căn 3/2