Question

Cho sinα=\(\dfrac{1}{3}\). Tính P= \(\dfrac{\tan\alpha+\cot\alpha}{\tan\alpha-3\cot\alpha}\)

Answer 1

\(P=\dfrac{\dfrac{sina}{cosa}+\dfrac{cosa}{sina}}{\dfrac{sina}{cosa}-\dfrac{3cosa}{sina}}=\dfrac{sin^2a+cos^2a}{sin^2a-3cos^2a}=\dfrac{1}{sin^2a-3\left(1-sin^2a\right)}=\dfrac{1}{4sin^2a-3}=\dfrac{1}{4.\left(\dfrac{1}{3}\right)^2-3}=...\)