Question

 

Cho R1=10Ω,A1=1,2A,A=1,8A

a)Tính U_AB

b)Tính R₂

Answer 1

\(a,U_m=U_1=U_2=R_1.I_1=10.1,2=12\left(V\right)\)

\(b,I_2=I_m-I_1=1,8-1,2=0,6\left(A\right)\)

\(R_2=\dfrac{U_2}{I_2}=\dfrac{12}{0,6}=20\left(\Omega\right)\)

Answer 2

a)

U\(_{AB}\) = U\(_1\) = \(R_1\).\(I_1\) = 1,2 . 10 = 12 ( V)

b) 

\(I_2\) = \(I_{ }\) - \(I_1\) = 1,8 - 1,2 = 0,6 ( A)

\(R_2\) = \(\dfrac{U_{AB}}{I_2}\) = \(\dfrac{12}{0,6}\) = 20 ( ÔM )