Question

Cho pt x^2-(2m-3)x-1=0 giải pt với m =1

Answer 1

\(pt:x^2-\left(2m-3\right)x-1=0\)

\(Thay\cdot m=1:pt\Leftrightarrow x^2+x-1=0\\ \Delta=1^2-4.\left(-1\right).1=5>0\\ \Rightarrow\left\{{}\begin{matrix}x_1=\frac{-1+\sqrt{5}}{2}\\x_2=\frac{-1-\sqrt{5}}{2}\end{matrix}\right.\)