Z gồm : \(H_2(a\ mol) ; H_2S(b\ mol)\)
\(n_Z = a + b = \dfrac{5,6}{22,4} = 0,25(mol)\\ m_Z = 2a + 34b = 0,25.2.7,4 = 3,7(gam)\\ \Rightarrow a = 0,15 ; b = 0,1\\ ZnS + 2HCl \to ZnCl_2 + H_2S\\ Zn + 2HCl \to ZnCl_2 + H_2\\ Zn + S \xrightarrow{t^o} ZnS\\ n_{Zn} = n_{ZnS} + n_{Zn\ dư} = n_{H_2S} + n_{H_2} = 0,25(mol)\\ n_S = n_{H_2S} = 0,1(mol)\\ \Rightarrow m = 0,25.65 + 0,1.32 = 19,45(gam)\)