Cho: \(\left\{{}\begin{matrix}a,b,c>0\\a+b+c=1\end{matrix}\right.\)
CMR: (\(\frac{1}{a}-1\))(\(\frac{1}{b}-1\))(\(\frac{1}{c}-1\)) ≥ 8
Cho \(\left\{{}\begin{matrix}x,y,z\ge0\\x+y+z=1\end{matrix}\right.\) Chứng minh \(x^3+y^3+z^3+6xyz\ge\frac{1}{4}\)
Cho \(\left\{{}\begin{matrix}x,y,z\ge0\\x+y+z=1\end{matrix}\right.\) Chứng minh \(0\le xy+yz+zx-2xyz\le\frac{7}{27}\)
Cho \(\left\{{}\begin{matrix}x,y,z\ge0\\x+y+z=1\end{matrix}\right.\). Chứng minh \(x^2y+y^2z+z^2x\le\frac{4}{27}\)
Cho a,b>0 . Chứng minh \(\frac{1}{a}+\frac{1}{b}\ge\frac{4}{a+b}\) (1). Áp dụng cm các bđt sau:
a)\(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\ge2\left(\frac{1}{a+b}+\frac{1}{b+c}+\frac{1}{c+a}\right)\) với a,b,c>0
b)\(\frac{1}{a+b}+\frac{1}{b+c}+\frac{1}{c+a}\ge2\left(\frac{1}{2a+b+c}+\frac{1}{a+2b+c}+\frac{1}{a+b+2c}\right)\) với a,b,c>0
c)Cho a,b,c>0 tm \(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=4\) . CM \(\frac{1}{2a+b+c}+\frac{1}{a+2b+c}+\frac{1}{a+b+2c}\le1\)
d) Cho a,b,c là độ dài 3 cạnh của 1 tam giác, p là nửa chu vi .CMR:
\(\frac{1}{p-a}+\frac{1}{p-b}+\frac{1}{p-c}\ge2\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)\)
Giải hpt :
1. \(\left\{{}\begin{matrix}x^2+xy\left(2y-1\right)=2y^3-2y^2-x\\6\sqrt{x-1}+y+7=4x\left(y-1\right)\end{matrix}\right.\)
2. \(\left\{{}\begin{matrix}x\sqrt{x^2+y}+y=\sqrt{x^4+x^2}+x\\x+\sqrt{y}+\sqrt{x-1}+\sqrt{y\left(x-1\right)}=\frac{9}{2}\end{matrix}\right.\)
3.
Cho hàm số \(y=f\left(x\right)=\left\{{}\begin{matrix}\frac{1}{x-1}khix\le0\\\sqrt{x+2}khix>0\end{matrix}\right.\). Tính P=f(0+f(2)
Cho a,b,c>0 chứng minh \(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\ge\frac{9}{a+b+c}\) (1). Áp dụng chứng minh các BĐT sau:
a) \(\left(a^2+b^2+c^2\right)\left(\frac{1}{a+b}+\frac{1}{b+c}+\frac{1}{c+a}\right)\ge\frac{3}{2}\left(a+b+c\right)\)
b) Cho x,y,z>0 tm x+y+z=1. Tìm GTLN của bt \(P=\frac{x}{x+1}+\frac{y}{y+1}+\frac{z}{z+1}\)
\(a\frac{3}{5}-\left(-\frac{1}{2}\right)+\frac{2}{5} b\frac{3}{7}.19\frac{1}{3}-\frac{3}{7}.33\frac{1}{3}c\left(\frac{3^4}{5}\right).\left(\frac{5^3}{3}\right)d\frac{11}{23}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}\)