Question

cho hàm số y=f(x)=x^2+3. Tính f(0),f(-1/3)

Answer 1

\(f\left(0\right)=0^2+3=3\)
\(f\left(-\dfrac{1}{3}\right)=\left(-\dfrac{1}{3}\right)^2+3=\dfrac{10}{3}\)

Answer 2

f(0)=3

Answer 3

cho hàm số y=f(x)=x^2+3. Tính f(0),f(-1/3)

Ta có:

f(0)=\(0^2+3\) = 3

f(-1/3) = \(\left(\dfrac{-1}{3}\right)^2\) + 3 = \(\dfrac{28}{9}\)