Question

cho hàm số y=f(x) =x\(^2\) - 2. Tính f(2), f(1), f(0), f(-1), f(7)

Answer 1

\(f\left(2\right)=2^2-2=2\)

\(f\left(1\right)=1^2-2=-1\)

\(f\left(0\right)=0^2-2=-2\)

\(f\left(-1\right)=\left(-1\right)^2-2=-1\)

\(f\left(7\right)=7^2-2=47\)

Answer 2

Ta có : y=f(x) =x\(^2\) - 2

f(2) = 2\(^2\) – 2 = 4 – 2 = 2f(1) = 1\(^2\) – 2 = 1 – 2 = – 1f(0) = 0\(^2\) – 2 = 0 – 2= – 2f(-1) = (-1)\(^2\) – 2 = 1 – 2= – 1f(7) = (7)\(^2\) – 2 = 49 – 2 = 47

Answer 3

ta có :y=f(x)=x²-2

=>f(2)=2²-2=4-2=2

f(1)=1² -2=1-2= -1

f(0)=0² -2 =0-2=-2

f(-1) =(-1)² -2=1-2= -1

f(7)=7² - 2 =49-2 =47