a. f(-1) = 2.(-1)+1 = -2+1 = -1
g(-1) = 1-2.(-1) = 1+2 = 3
Vậy f(-1) = -1 và g(-1) = 3
c. Cách 1: f(x) = g(x)
\(\Rightarrow f\left(x\right)-g\left(x\right)=0\)
\(\Rightarrow\) (2x+1) - (1-2x) = 0
\(\Rightarrow\) 2x+1-1+2x = 0
\(\Rightarrow\) 2x+2x = -1+1
\(\Rightarrow4x=0\)
\(\Rightarrow\) x = 0
Vậy \(f\left(x\right)=g\left(x\right)\Leftrightarrow x=0\)
Cách 2:
f(x) = g(x)
\(\Rightarrow\) 2x+1 = 1-2x
\(\Rightarrow\) 2x+2x = 1-1
\(\Rightarrow\) 4x = 0
\(\Rightarrow\) x = 0
Vậy \(f\left(x\right)=g\left(x\right)\Leftrightarrow x=0\)