f(x) có :
\(\dfrac{101-1}{2}+1=51\)(số hạng)
\(\Rightarrow f\left(1\right)=1+1^3+1^5+1^7+..+1^{101}\)
\(=1+1+1+1+...+1\\ =51\)
\(f\left(-1\right)=1+\left(-1\right)^3+\left(-1\right)^5+\left(-1\right)^7+...+\left(-1\right)^{101}\)
\(=1-1-1-1-...-1\)
\(=-49\)