Question

Cho 

\(\frac{3x-y}{x+y}=\frac{3}{4}\).Tính \(\frac{x}{y}\)

Answer 1

\(\Rightarrow4\left(3x-y\right)=3\left(x+y\right)\)

\(\Rightarrow12x-4y=3x+3y\)

\(\Rightarrow9x=7y\)

\(\Rightarrow\frac{x}{y}=\frac{7}{9}\)

Answer 2

ta có : \(\frac{3x-y}{x+y}=\frac{3}{4}\)

<=> 12x-4y=3x+3y

<=> 9x=7y

<=>\(\frac{x}{y}=\frac{7}{9}\)

Answer 3

\(\frac{3x-y}{x+y}=\frac{3}{4}\)

Ta có:4.(3x-y)=3.(x+y)

          12x-4y=3x+3y

           12x-3x=4y+3y

           9x=7y

Sau đó tự làm

Answer 4

\(\frac{3x-y}{x+y}=\frac{3}{4}\)

=>\(4\left(3x-y\right)=3\left(x+y\right)\)

=>\(12x-4y=3x+3y\)

=>\(9x=7y\)

=>\(\frac{x}{y}=\frac{7}{9}\)

Answer 5

tối mai bạn sẽ có câu trả lời

Answer 6

⇒ 4 (3x − y) = 3 (x + y)

⇒ 12x − 4y = 3x + 3y

⇒ 9x = 7y

⇒ \(\frac{x}{y}\)=\(\frac{7}{9}\)