\(x^3+y^3=2\Leftrightarrow\left(x+y\right)^3-3xy\left(x+y\right)=2\)
\(\Leftrightarrow1-3xy=2\Rightarrow xy=-\frac{1}{3}\)
\(\Rightarrow x^2+y^2=\left(x+y\right)^2-2xy=\frac{5}{3}\)
\(x^5+y^5=\left(x^3+y^3\right)\left(x^2+y^2\right)-\left(xy\right)^2\left(x+y\right)=2.\frac{5}{3}-\frac{1}{9}=\frac{29}{9}\)