a) ĐKXĐ: 4x2-4x+1>0
(2x)2-2.2x+1= (2x-1)2≥ 0
b) P= \(\frac{8x^3-12x^2+6x-1}{4x^2-4x+1}\) = \(\frac{\left(2x\right)^3-3.\left(2x\right)^2.1+3.2x.1-1}{\left(2x-1\right)^2}\) = \(\frac{\left(2x-1\right)^3}{\left(2x-1\right)^2}\) = 2x-1 c) ta có: x ∈ Z ⇒ 2.x ∈ Z ⇔2x-1 ∈ Z