a: Ta có: \(\widehat{DAO}=\dfrac{\widehat{DAB}}{2}\)
\(\widehat{ADO}=\dfrac{\widehat{ADC}}{2}\)
Do đó: \(\widehat{DAO}+\widehat{ADO}=\dfrac{1}{2}\left(\widehat{DAB}+\widehat{ADC}\right)=\dfrac{1}{2}\cdot180^0\)
hay \(\widehat{DAO}+\widehat{ADO}=90^0\)
Xét ΔDAO có \(\widehat{DAO}+\widehat{ADO}=90^0\)
nên ΔDAO vuông tại O
Suy ra: AE\(\perp\)BD tại O