Ta có: \(\dfrac{a}{b}=\dfrac{c}{d}\)
\(\Rightarrow\dfrac{a}{c}=\dfrac{b}{d}=\dfrac{a+b}{c+d}=\dfrac{a-b}{c-d}\)
\(\Rightarrow\left(a+b\right).\left(c-d\right)=\left(a-b\right).\left(c+d\right)\)
\(\Rightarrow\dfrac{a-b}{a+b}=\dfrac{c-d}{c+d}\left(đpcm\right)\)