a: \(A=\left(x^3\cdot\left(\dfrac{x+1+2\sqrt{x}+x+1-2\sqrt{x}}{x+1}\right)\right)^2-4x^6+x^4+3x^2-4\)
\(=4x^6-4x^6+x^4+3x^2-4\)
\(=x^4+3x^2-4\)
Khi x=2 thì \(A=16+3\cdot4-4=16+8=24\)
b: Khi \(A=8x^2-8\) thì \(x^4+3x^2-4=8x^2-8\)
\(\Leftrightarrow x^4-5x^2+4=0\)
\(\Leftrightarrow\left(x-1\right)\left(x+1\right)\left(x+2\right)\left(x-2\right)=0\)
=>x=1 hoặc x=2