\(n_{FeS}=\frac{17,6}{88}=0,2\left(mol\right)\)
PTHH :
\(FeS+2HCl\rightarrow FeCl_2+H_2S\)
0,2_____________________0,2 (mol)
\(CuSO_4+H_2S\rightarrow CuS+H_2SO_4\)
0,2______0,2__________________(mol)
\(\Rightarrow m_{dd\left(CuSO4\right)}=\frac{0,2.160.100}{10}=320\left(g\right)\)
\(d_{CuSO4}=\frac{320}{291}=1,02\left(\frac{g}{ml}\right)\)