\(m_O=\dfrac{15.12,8}{100}=1,92\left(g\right)\)
=> \(n_O=\dfrac{1,92}{16}=0,12\left(mol\right)\)
=> \(n_{H_2O}=0,12\left(mol\right)\)
\(n_{H_2}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\)
Bảo toàn H: nHCl = 0,12.2 + 0,15.2 = 0,54 (mol)
=> nCl = 0,54 (mol)
mmuối = mhh rắn - mO + mCl
= 15 - 1,92 + 0,54.35,5 = 32,25 (g)