\(n_{OH^-}=0,01.0,1=0,001\left(mol\right)\)
\(n_{H^+}=0,015.0,1=0,0015\left(mol\right)\)
\(\Rightarrow n_{H^+dư}=0,0005\left(mol\right)\)
\(\Rightarrow\left[H^+\right]=\dfrac{0,0005}{0,01+0,015}=0,02\left(mol\right)\)
\(\Rightarrow pH\approx1,7\)
\(\Rightarrow\) Quỳ tím hóa đỏ.