1\(\dfrac{5}{7}\) . 0,75 - \(\dfrac{6}{7}.1\dfrac{1}{3}+\dfrac{6}{7}\)
= \(\dfrac{12}{7}.0,75-\dfrac{6}{7}.\dfrac{4}{3}+\dfrac{6}{7}\)
= \(\dfrac{6}{7}.2.0,75-\dfrac{6}{7}.\dfrac{4}{3}+\dfrac{6}{7}\)
= \(\dfrac{6}{7}.\left(2.0,75-\dfrac{4}{3}+1\right)\)
= \(\dfrac{6}{7}.\dfrac{7}{6}\)
=1