\(m_{CuSO_4}=\dfrac{160\cdot10}{100}=16\left(g\right)\)
\(\Rightarrow m_{H_2O}=m_{dd}-m_{CuSO_4}=160-16=144\left(g\right)\)
\(\Rightarrow m_{ddsau}=\dfrac{144}{\left(100-25\right)}\cdot100=192\left(g\right)\)
\(m_{CuSO_4\left(ct\right)}=192-160=32\left(g\right)\)