Ta có:
264kg = 264000g
\(\Rightarrow n_{\left(NH4\right)_2SO_4}=264000:132=2000\left(mol\right)\)
\(\Rightarrow n_N=2000.7=16000\left(mol\right)\)
Vậy số mol N trong \(Ca\left(No_3\right)_2=16000:2=8000\left(mol\right)\)
\(\Rightarrow m_{Ca\left(NO_3\right)_2}=8000.164=1312000g=1312kg\)