Bài 1:
\(\Leftrightarrow\left(2x-1\right)^6-\left(2x-1\right)^4=0\)
=>2x(2x-1)(2x-2)=0
hay \(x\in\left\{0;\dfrac{1}{2};1\right\}\)
Bài 3:
\(\dfrac{a+5}{a-5}=\dfrac{b+6}{b-6}\)
\(\Leftrightarrow\dfrac{a-5+10}{a-5}=\dfrac{b-6+12}{b-6}\)
\(\Leftrightarrow\dfrac{10}{a-5}=\dfrac{12}{b-6}\)
\(\Leftrightarrow\dfrac{a-5}{5}=\dfrac{b-6}{6}\)
\(\Leftrightarrow\dfrac{a}{5}=\dfrac{b}{6}\)
hay a/b=5/6