Câu 2:
\(10\dfrac{1}{4}:\left(-1\dfrac{4}{5}\right)-37\dfrac{1}{4}:\left(-1\dfrac{4}{5}\right)\)
\(=\dfrac{41}{4}\cdot\dfrac{-5}{9}-\dfrac{149}{4}\cdot\dfrac{-5}{9}\)
\(=\dfrac{-5}{9}\left(\dfrac{41}{4}-\dfrac{149}{4}\right)=\dfrac{-5}{9}\cdot\dfrac{-108}{4}=-\dfrac{5}{9}\cdot\left(-27\right)=15\)