Question

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Phân tích thành nhân tử:
1) 
2) 
3) 
4) 
Xin cảm ơn

Answer 1

\(1,12x^2y-27y^3=3y\left(4x^2-9y^2\right)=3y\left(2x+3y\right)\left(2x-3y\right)\\ 2,4x^2-36=4\left(x^2-9\right)=4\left(x-3\right)\left(x+3\right)\\ 3,x^2-4x+4-y^2=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x+y-2\right)\\ 4,\left(3x+1\right)^2-\left(x-2\right)^2=\left(3x+1-x+2\right)\left(3x+1+x-2\right)=\left(2x+3\right)\left(4x-1\right)\)

Answer 2

\(1,=3y\left(4x^2-9y^2\right)=3y\left(2x+3y\right)\left(2x-3y\right)\)

\(2,=4\left(x^2-9\right)=4\left(x-3\right)\left(x+3\right)\)

\(3,=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x-y+2\right)\)

\(4,=\left(3x+1-x+2\right)\left(3x+1+x-2\right)=\left(2x+3\right)\left(4x-1\right)\)