a) \(ab^2\cdot\sqrt{\dfrac{3}{a^2b^4}}=ab^2\cdot\dfrac{\sqrt{3}}{-ab^2}=-\sqrt{3}\)
b) \(\sqrt{\dfrac{27\left(a-3\right)^2}{48}}=\sqrt{\dfrac{9\left(a-3\right)^2}{16}}=\dfrac{3}{4}\left(a-3\right)=\dfrac{3}{4}a-\dfrac{9}{4}\)
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