Ta có: \(\left\{{}\begin{matrix}a\perp c\\b\perp c\end{matrix}\right.\) => a//b.
\(\Rightarrow\widehat{A_3}+\widehat{B_4}=180^0\)(2 góc trong cùng phía)
\(\Rightarrow\widehat{A_3}=180^0-\widehat{B_4}=180^0-60^0=120^0\)
\(\Rightarrow\widehat{A_2}=\widehat{A_3}=120^0\) (2 góc đối đỉnh)