Question

b,x-2/7+2-1/8=x-4/5+x-3/6

Answer 1

Sửa đề: \(\dfrac{x-2}{7}+\dfrac{x-1}{8}=\dfrac{x-4}{5}+\dfrac{x-3}{6}\)

=>\(\dfrac{x-2}{7}-1+\dfrac{x-1}{8}-1=\dfrac{x-4}{5}-1+\dfrac{x-3}{6}-1\)

=>x-9=0

=>x=9