\(=\dfrac{\sqrt{x}\left(x-1\right)^2}{x+1}:\left[\left(x+\sqrt{x}+1+\sqrt{x}\right)\left(x-\sqrt{x}+1-\sqrt{x}\right)\right]\)
\(=\dfrac{\sqrt{x}\left(x-1\right)^2}{x+1}:\left(x-1\right)^2=\dfrac{\sqrt{x}}{x+1}\)
a) \(\left(\dfrac{1}{\sqrt{x}}-\dfrac{1}{x}\right):\left(\dfrac{\sqrt{x}+1}{\sqrt{x}-2}-\dfrac{\sqrt{x}+2}{\sqrt{x}-1}\right)\)
b) \(\left(\dfrac{\sqrt{a}-1}{\sqrt{a}+1}-\dfrac{\sqrt{a}+1}{\sqrt{a}-1}\right).\left(\sqrt{a}-\dfrac{1}{a}\right)\)
Rút gọn
A=\(\left(\dfrac{\sqrt{x}}{3+\sqrt{x}}+\dfrac{2x}{9-x}\right)\div\left(\dfrac{\sqrt{x}+1}{x-3\sqrt{x}}-\dfrac{2}{\sqrt{x}}\right)\)
B=\(\left(\dfrac{1}{x+\sqrt{x}}-\dfrac{1}{\sqrt{x}+1}\right)\div\dfrac{\sqrt{x}-1}{x+2\sqrt{x}+1}+1\)
rút gọn
C=\(\left(\dfrac{1}{\sqrt{x}-2}+\dfrac{1}{\sqrt{x}+2}\right)\div\dfrac{\sqrt{x}}{x-4}vớix>0,x\ne4\)
D=\(\dfrac{8+x\left(1+\sqrt{x-2\sqrt{x+1}}\right)}{\left(x-4\right)\left(x-2\sqrt{x}+4\right)}+\dfrac{x-3\sqrt{x}}{2\left(x-\sqrt{x}-6\right)}vớix>1,x\ne4,x\ne9\)
lm nhanhgiups mk nhé!Mk đang cần gấp!
Rút gọn biểu thức
a,\(\frac{1}{\left(2\sqrt{x}-2\right)}-\frac{1}{\left(2\sqrt{x}+2\right)}+\frac{\sqrt{x}}{\left(1-x\right)}\)
b, \(\left(\dfrac{\sqrt{x}-\sqrt{y}}{1+\sqrt{xy}}+\dfrac{\sqrt{x}+\sqrt{y}}{1-\sqrt{xy}}\right):\left(\dfrac{x+y+2xy}{1-xy}+1\right)\)
c, \(\dfrac{3\left(x+\sqrt{x}-3\right)}{x+\sqrt{x}-2}+\dfrac{\sqrt{x}+3}{\sqrt{x}+2}-\dfrac{\sqrt{x}-2}{\sqrt{x}-1}\)
Rút gọn:
A=\(\left(\dfrac{x-\sqrt{x}+2}{x-\sqrt{x}-2}-\dfrac{x}{x-2\sqrt{x}}\right)\div\dfrac{1-\sqrt{x}}{2-\sqrt{x}}vớix>0,x\ne1\)
B=\(\left(\dfrac{x}{3+\sqrt{x}}+\dfrac{1}{\sqrt{x}+3}\right)\div\left(1-\dfrac{2}{\sqrt{x}}+\dfrac{6}{x+3\sqrt{x}}\right)\)
Lm nhanh giúp mk nhé!
Tìm x, bt :
a, \(\left(\dfrac{1}{\sqrt{x}-1}-\dfrac{1}{\sqrt{x}}\right):\left(\dfrac{\sqrt{x}+1}{\sqrt{x}-2}-\dfrac{\sqrt{x}+2}{\sqrt{x}-1}\right)>0\)
b, \(\left(\dfrac{1}{\sqrt{x}-1}-\dfrac{3}{x\sqrt{x}+1}+\dfrac{3}{x-\sqrt{x}+1}\right)>1\)rút gọn
A=\(\left(\dfrac{x-\sqrt{x}+2}{x-\sqrt{x}-2}-\dfrac{x}{x-2\sqrt{x}}\right)\div\dfrac{1-\sqrt{x}}{2-\sqrt{x}}\)
B=\(\left(\dfrac{1}{2\sqrt{x}+1}+\dfrac{1}{2\sqrt{x}-1}\right)\div\dfrac{1}{1-4x}\)
A= \(\left[\left(\dfrac{2\sqrt{x}}{\sqrt{x}+3}\right)+\dfrac{\sqrt{x}}{\sqrt{x}+3}+3\left(\dfrac{\sqrt{x}}{x-9}\right)\right]:\left(\dfrac{2\sqrt{x}-2}{\sqrt{x}-3}-\dfrac{1}{1}\right)\)với x>= 0 , x #9
Cho Q=\(\left(\dfrac{x-1}{\sqrt{x}-1}-\dfrac{x\sqrt{x}-1}{x-1}\right):\left(\dfrac{\left(\sqrt{x}-1\right)^2}{\sqrt{x}+1}+\dfrac{\sqrt{x}}{\sqrt{x}+1}\right)^2\)
a;Rút gọn Q với x≥0;x≠1
b;Tìm x để Q<1
