BCNN (4, 5)
Ta có : 4 = 22 ; 5 = 5
=> BCNN (4, 5) = 22 . 5 = 20
UCLN (6, 12)
Ta có : 6 = 2 . 3 ; 12 = 22 . 3
=> UCLN (6, 12) = 2 . 3 = 6
BCNN(4,5)
Ta có:4=22;5=5
=>BCNN(4,5)=22.5=20
UCLN(6,12)
C1:Ta có:6=2.3;12=22.3
=>UCLN(6,12)=2.3=6
C2:Vì:12 chia hết cho 6=>6 la UCLN(6,12)