\(f\left(x\right)=\left(m+2\right)x^2+2\left(m+2\right)x+m+3>0\) ∀x
\(\Leftrightarrow\left\{{}\begin{matrix}a>0\\\Delta'< 0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}m+2>0\\\left(m+2\right)^2-\left(m+2\right)\left(m+3\right)< 0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}m>-2\\m^2+4m+4-m^2-5m-6< 0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}m>-2\\-m-2< 0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}m>-2\\m>-2\end{matrix}\right.\)
Vậy m>-2