a: ta có: \(\widehat{MAP}=\widehat{NAQ}\)(hai góc đối đỉnh)
mà \(\widehat{MAP}=60^0\)
nên \(\widehat{NAQ}=60^0\)
b: ta có: \(\widehat{NAQ}+\widehat{MAQ}=180^0\)(hai góc kề bù)
=>\(\widehat{MAQ}+60^0=180^0\)
=>\(\widehat{MAQ}=120^0\)
c: Các cặp góc đối đỉnh là:
\(\widehat{MAP};\widehat{NAQ}\)
\(\widehat{MAQ};\widehat{NAP}\)
d: Các cặp góc bù nhau là:
\(\widehat{MAQ};\widehat{MAP}\)
\(\widehat{MAQ};\widehat{NAQ}\)
\(\widehat{MAP};\widehat{NAP}\)
\(\widehat{NAP};\widehat{NAQ}\)