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Ta có: \(A=\sqrt{x^2+2x+1}+\sqrt{x^2-2x+1}\)
\(\Leftrightarrow A=\sqrt{\left(x+1\right)^2}+\sqrt{\left(x-1\right)^2}\)
\(\Leftrightarrow A=\left|x+1\right|+\left|1-x\right|\ge\left|x+1+1-x\right|=2\)
Vậy GTNN của A là 2 <=> \(x+1=1-x\Rightarrow x=0\)