ĐKXĐ : \(m\ne\pm\frac{1}{2}\)
Ta có : \(A.B=A+B\)
=> \(\frac{5.4}{\left(2m+1\right)\left(2m-1\right)}=\frac{5}{2m+1}+\frac{4}{2m-1}\)
=> \(5\left(2m-1\right)+4\left(2m+1\right)=20\)
=> \(10m-5+8m+4=20\)
=> \(18m=21\)
=> \(m=\frac{7}{6}\) ( TM )
Vậy .................