Phép nhân và phép chia các đa thức

Mai

bài 2:

a) x2+2/x3-1 + 2/x2+x+1 + 1/1-x

b) 9/x3-9x - (-1)/x+3

c) x3-8/5x+10 . x2+4x/x2+2x+4

d)5x+10/4x-8 . 4-2x/x+2

e) (x-13)2/2x5 . (-3x2)/x-13

g) x2+6x+9/1-x . (x-1)2/2(x+3)2

Hải Ngân
1 tháng 1 2018 lúc 22:30

a) \(\dfrac{x^2+2}{x^3-1}+\dfrac{2}{x^2+x+1}+\dfrac{1}{1-x}\)

\(=\dfrac{x^2+2}{\left(x-1\right)\left(x^2+x+1\right)}+\dfrac{2}{x^2+x+1}-\dfrac{1}{x-1}\)

\(=\dfrac{x^2+2+2\left(x-1\right)-\left(x^2+x+1\right)}{\left(x-1\right)\left(x^2+x+1\right)}\)

\(=\dfrac{x^2+2+2x-2-x^2-x-1}{\left(x-1\right)\left(x^2+x+1\right)}\)

\(=\dfrac{x-1}{\left(x-1\right)\left(x^2+x+1\right)}\)

\(=\dfrac{1}{x^2+x+1}\)

b) \(\dfrac{9}{x^3-9x}-\dfrac{-1}{x+3}\)

\(=\dfrac{9}{x\left(x-3\right)\left(x+3\right)}+\dfrac{1}{x+3}\)

\(=\dfrac{9+x\left(x-3\right)}{x\left(x-3\right)\left(x+3\right)}\)

\(=\dfrac{9+x^2-3x}{x\left(x-3\right)\left(x+3\right)}\)

c) \(\dfrac{x^3-8}{5x+10}.\dfrac{x^2+4x}{x^2+2x+4}\)

\(=\dfrac{x\left(x-2\right)\left(x^2+2x+4\right)\left(x+4\right)}{5\left(x+2\right)\left(x^2+2x+4\right)}\)

\(=\dfrac{x\left(x-2\right)\left(x+4\right)}{5\left(x+2\right)}\)

d) \(\dfrac{5x+10}{4x-8}.\dfrac{4-2x}{x+2}\)

\(=\dfrac{5\left(x+2\right)}{4\left(x-2\right)}.\dfrac{2\left(2-x\right)}{x+2}\)

\(=-\dfrac{10\left(x+2\right)\left(x-2\right)}{4\left(x-2\right)\left(x+2\right)}\)

\(=-\dfrac{5}{2}\)

e) \(\dfrac{\left(x-13\right)^2}{2x^5}.\dfrac{-3x^2}{x-13}\)

\(=\dfrac{x-13}{2x^3}.\dfrac{-3}{1}\)

\(=\dfrac{-3\left(x-13\right)}{2x^3}\)

g) \(\dfrac{x^2+6x+9}{1-x}.\dfrac{\left(x-1\right)^2}{2\left(x+3\right)^2}\)

\(=-\dfrac{\left(x+3\right)^2}{x-1}.\dfrac{\left(x-1\right)^2}{2\left(x+3\right)^2}\)

\(=-\dfrac{\left(x+3\right)^2\left(x-1\right)^2}{2\left(x-1\right)\left(x+3\right)^2}\)

\(=-\dfrac{x-1}{2}\).

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