a; Ta có: DM//AB
nên \(\widehat{BAC}=\widehat{DMC}\)(hai góc đồng vị)
b: Ta có: \(\widehat{BAC}=\widehat{DMC}\)
nên \(\widehat{MAD}=\widehat{DMC}\)
mà \(\widehat{MAD}=\widehat{MDA}\left(=\widehat{BAD}\right)\)
nên \(\widehat{DMC}=\widehat{MDA}\)
=>MK//AD